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/* eslint no-shadow: 0 */
const test = require("tap").test;const ss = require("../dist/simple-statistics.js");
test("sum", function (t) {    t.test("can get the sum of two numbers", function (t) {        t.equal(ss.sum([1, 2]), 3);        t.end();    });
    t.test("the sum of no numbers is zero", function (t) {        t.equal(ss.sum([]), 0);        t.end();    });
    t.test("returns NaN if a non-number is given", function (t) {        t.ok(isNaN(ss.sum([1, null])));        t.ok(isNaN(ss.sum([null, 1])));        t.ok(isNaN(ss.sum([1, 2, null])));        t.ok(isNaN(ss.sum([1, 2, true])));        t.end();    });    t.end();});
test("sumSimple", function (t) {    t.test("can get the sum of two numbers", function (t) {        t.equal(ss.sumSimple([1, 2]), 3);        t.end();    });
    t.test("can get the sum of two numbers", function (t) {        t.equal(            ss.sumSimple([                0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0, 1.1, 1.2, 1.3,                1.4, 1.5, 1.6, 1.7            ]),            15.299999999999999        );        t.equal(            ss.sum([                0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0, 1.1, 1.2, 1.3,                1.4, 1.5, 1.6, 1.7            ]),            15.3        );        t.end();    });
    t.test("the sum of no numbers is zero", function (t) {        t.equal(ss.sumSimple([]), 0);        t.end();    });
    t.test("same NaN behavior as sum", function (t) {        t.ok(isNaN(ss.sumSimple([null])));        t.ok(isNaN(ss.sumSimple([1, 2, null])));        t.end();    });    t.end();});